Question

The fraction $\frac{\sqrt{3}-\sqrt{2}}{\sqrt{2}}$ is equal to

• A. $\sqrt{3}$
• B. $\frac{\sqrt{3}-2}{2}$
• C. $\sqrt{6}$
• D. $\frac{\sqrt{6}-2}{2}$
• E. $\sqrt{3}-1$

Answer 1

The correct option is D $\frac{\sqrt{6}-2}{2}$

After multiplying denominator & numerator with $\sqrt{2}$

$\frac{(\sqrt{3}-\sqrt{2})\times \sqrt{2}}{\sqrt{2}\times \sqrt{2}}$

$\frac{\sqrt{6}-2}{2}$.