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Question

The fraction 3xax+axa becomes 00 when x=a.

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Solution

limxa3xax+axa
Since it goes to 00 form we shall rationalize the numerator
We know that (a+b)(ab)=a2b2; thus multiplying numerator and denominator with 3xa+x+a to rationalize
=limxa3xaxa(xa)(3xa+x+a)
=limxa2(xa)(xa)(3xa+x+a)
=limxa2(3xa+x+a)
=22.2a
=12a

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