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Question

The fraction of the original number of a radioactive atom having a mean life of 10 days, that decays during the 5th day is :

A
0.15
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B
0.3
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C
0.045
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D
0.064
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Solution

The correct option is C 0.064
Tav=10days=1λ

Number of decays during 5th day =N0eλ4N0eλ5

Fraction decayed during 5th day =e4λe5λ

=e4/10e1/2=0.06370.064

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