wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The fractional part of a real number x is x[x], where [x] is the greatest integer less than or equal to x. Let F1 and F2 be the fractional parts of (442017)2017 and (44+2017)2017 respectively. Then F1+F2 lies between the numbers

A
0 and 0.45
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.45 and 0.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.9 and 1.35
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.35 and 1.8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.9 and 1.35
Given, F1 and F2 be the fractional parts of (442017)2017 and (44+2017)2017 respectively.

Therefore,
(442017)2017=0+F1 [2017=44.91]
and (44+2017)2017=I1+F2

Using binomial expansion,
(442017)2017=2017C0(44)20172017C1(44)2016(2017)+2017C2(44)2015(2017)2(2017)2017=0+F1 (i)
(44+2017)2017=2017C0(44)2017+2017C1(44)2016(2017)+2017C2(44)2015(2017)2++(2017)2017=I1+F2 (ii)

Adding equation (i) and (ii), we get
I1+F1+F2=2[2017C0(44)2017+2017C2(44)2015(2017)2++2017C2(44)1(2017)2016]
I1+F1+F2=I2, where I2 is integer.
F1+F2 is an integer.

0<F1<1
0<F2<1
0<F1+F2<2
Between 0 and 2, only integer is 1.
F1+F2=1 which lies between 0.9 and 1.35

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Binomial Theorem for Any Index
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon