CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The free end of the open-link chain of total L and mass per unit λ is released from rest at x = 0. The thrust force at the lower end of non-moving part due to relative motion of other part as a function of x is :

A
2λgx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
λgx
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2λgx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B λgx
Thrust force at the lower end of non-moving part is equals to m'g where m' is the mass of the moving part.
Representing m' as a function of x: m=x×λ
Therefore the thrust force at the lower end of non-moving part due to relative motion of other part as a function of x : =mg=xλg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
How Do Rockets Fly in Space?
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon