The free end of the open-link chain of total L and mass per unit λ is released from rest at x = 0. The thrust force at the lower end of non-moving part due to relative motion of other part as a function of x is :
A
2λgx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
λgx
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
√2λgx
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Bλgx Thrust force at the lower end of non-moving part is equals to m'g where m' is the mass of the moving part.
Representing m' as a function of x: m′=x×λ
Therefore the thrust force at the lower end of non-moving part due to relative motion of other part as a function of x : =m′g=xλg