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Question

The free end of the open-link chain of total L and mass per unit λ is released from rest at x = 0. The thrust force at the lower end of non-moving part due to relative motion of other part as a function of x is :

A
2λgx
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B
λgx
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C
2λgx
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D
Zero
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Solution

The correct option is B λgx
Thrust force at the lower end of non-moving part is equals to m'g where m' is the mass of the moving part.
Representing m' as a function of x: m=x×λ
Therefore the thrust force at the lower end of non-moving part due to relative motion of other part as a function of x : =mg=xλg

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