The free energy change is related to equilibrium constant as

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Solution

The correct option is C

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Similar questions

The standard Gibbs free energy change, $Δ G^{0}$ is related to equilibrium constant, $K_{p}$ as:

Δ G^{o}

K_{P}

Gibbs energy change $Δ$ G is related to equilibrium constant K as:

(G)

G = - R T l n K

R

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