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Heterogeneous Catalysis

The free ener...

Question

The free energy change of a reversible reaction at equilibrium is

A

+ve

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B

Infinite

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C

Zero

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D

Negative

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Solution

The correct option is C
Zero

At equilibrium state, reaction neither forward nor reverse reaction favored

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Similar questions

Q. The free energy change for a reversible reaction at equilibrium is:

Q. The Gibbs energy change for a reversible reaction at equilibrium is:

Q. A reaction attains equilibrium when the free energy change accompanying it is:

Q. For a reaction at equilibrium, the value of Gibbs free energy change is:

Q. A reversible reaction proceeds in the direction that decreases the free energy of the system. There is an important relationship between the equilibrium constant and the standard free energy of the system given by

log K = \frac{- Δ G^{0}}{2.303} RT

This equation is applicable to all reversible processes and allows us to estimate the equilibrium constant from the standard free energy and the enthalpy change of the reaction.
Take

R = \frac{25}{3} J/molK, \frac{1}{12} L atm/molk, ln 2 = 0.7, ln 3 = 1.1, ln 5 = 1.6, log 2 = 0.3, log 3 = 0.5, l o g 5 = 0.7

The equilibrium constant for the dissociation of

N_{2} O_{4}

N O_{2}

27^{\circ}

C. What is the standard free energy change for this reaction?

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