wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The free energy of formation of NO is 78 kJ mol1 at the temperature of 1000 K. What is the equilibrium constant for this reaction at 1000 K?
12N2(g)+12O2(g)NO(g)

A
8.4×105
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7.1×109
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4.2×1010
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.7×1019
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 8.4×105
The relation between Gibbs free energy and K is given by
ΔG=2.303 RT logK
simplifying and taking antilog on both sides we get,
K= anti log [ΔG2.303RT] Putting the values we get,[78×10002.303×8.314×1000]=8.4×105

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon