The freezing point among the following equimolal aqueous solutions will be highest for :

C_{6} H_{5} N H_{3} C l

(aniline hydrochloride)

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C a {(N O_{3})}_{2}

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L a {(N O_{3})}_{3}

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C_{6} H_{12} O_{6}

(glucose)

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Solution

The correct option is D $C_{6} H_{12} O_{6}$ (glucose)
$C_{6} H_{5} N H_{3} C l ⟶ {C_{6} H_{5} N H_{3}}^{\oplus} + {C l}^{⊖}$
$C a {(N O_{3})}_{2} ⟶ {C a}^{2 +} + 2 N O_{3}^{⊖}$
$L a {(N O_{3})}_{3} ⟶ {L a}^{3 +} + 3 N O_{3}^{⊖}$
Glucose does not dissociate. It has the minimum number of particles, and therefore, it shows minimum depression in freezing point.

So, it has the maximum freezing point.

Option D is correct.

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Similar questions

$18.0 g$ of glucose $(C_{6} H_{12} O_{6})$ is added to $178.2 g$ of water. The vapour pressure of water for this aqueous solution at $100^{o} C$ is :

(C_{6} H_{12} O_{6})

10^{3} \times x

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