You visited us 1 times! Enjoying our articles? Unlock Full Access!

Depression in Freezing Point

The freezing ...

Question

The freezing point depression constant for water ids ${1.86}^{o} c m^{- 1}$ . If $5.0$ g of $N a_{2} S O_{4}$ is dissolved in $45.0$ g $H_{2} O$ , the freezing point is change by $- {3.82}^{o} C$ . Calculate the van't Hoff factor for $N a_{2} S O_{4}$ ?

0.381

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.05

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.63

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3.11

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2.63$
$Δ T_{f} = i K_{f} m$

$i = \frac{Δ T_{f} \times W_{1}}{Δ K_{f} \times n_{2} \times 1000}$

$= \frac{3.82 \times 45}{1.86 \times \frac{5}{142} \times 1000}$

$= 2.63$

Suggest Corrections

Similar questions

{1.86}^{o} C

m^{- 1}

5

N a_{2} S O_{4}

H_{2} O

- {3.82}^{o} C

N a_{2} S O_{4}

- {1.86}^{0} C m^{- 1} .

N a_{2} S O_{4}

H_{2} O,

{3.82}^{0} C .

N a_{2} S O_{4} .

5 g

N a_{2} S O_{4}

45 g

H_{2} O

{3.72}^{\circ} C

N a_{2} S O_{4}

{1.86}^{\circ} C k g m o l^{- 1}

0.0711

N a_{2} S O_{4}

- {0.320}^{o}

K_{f}

1.86

m o l^{- 1}

19.5 g

C H_{2} F C O O H

500 g

{1.00}^{0} C

Join BYJU'S Learning Program