Question

The freezing point of a $0.05$ molal solution of a non-electrolyte in water is:

• A. $-{0.093}^{\circ }C$
• B. ${1.86}^{\circ }C$
• C. ${0.93}^{\circ }C$
• D. ${0.093}^{\circ }C$

Answer 1

The correct option is A $-{0.093}^{\circ }C$

For non-electrolyte

$\Delta T_f=K_f\times m$

Given, $m=0.05$,

$\therefore \Delta T_f=1.86\times 0.05={0.093}^{\circ }C$

The freezing point of the solution

$T_f=1.86=0-\Delta T_f$

$=0-0.093=-{0.093}^{\circ }C$

Hence, the correct option is $A$