The freezing point of a 0.05 molal solution of non-electrolyte in water is:
$[K_{f} = 1.86 K m^{- 1}]$

- {1.86}^{o} C

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- {0.93}^{o} C

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- {0.093}^{o} C

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{0.093}^{o} C

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Solution

The correct option is B $- {0.093}^{o} C$
$Δ T_{f} = k_{f} \times m = 1.86 \times 0.05 = 0.093$ ;

$∴ T_{f} = 0 - 0.093 = - {0.093}^{o} C$

Hence, the correct option is $C$

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