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Byju's Answer
Standard XII
Chemistry
Abnormal Colligative Properties
The freezing ...
Question
The freezing point of a solution containing
0.2
g
of acetic acid in
20
g
of benzene is lowered by
0.
45
o
C
Calculate the degree of association of acetic acid in benzene (
K
f
for benzene is
5.12
K
kg
m
o
l
−
1
).
Open in App
Solution
Δ
T
f
=
i
k
f
m
⇒
0.45
=
i
×
5.12
×
0.2
60
20
×
1000
⇒
i
=
0.95
5.12
×
60
0.2
×
20
1000
=
0.527
2
C
H
3
C
O
O
H
⇌
(
C
H
3
C
O
O
H
)
2
1
−
α
a
/
2
∴
i
=
1
+
α
2
=
0.527
⇒
α
=
0.946
Answer.
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Similar questions
Q.
The freezing point of a solution containing
0.2
g of acetic acid in
20.0
g benzene is lowered by
0.45
o
C
. The degree of association of acetic acid in benzene is:
[Assume acetic acid dimerizes in benzene and
K
f
for benzene
=
5.12
K kg mol
−
1
]
Q.
The freezing point of benzene decreases by
0.45
o
C
when
0.2
g
of acetic acid is added to
20
g
of benzene. If acetic acid associates to form a dimer in benzene, percentage association of acetic acid in benzene will be :
(
K
f
for benzene
=
5.12
K
k
g
m
o
l
−
1
)
Q.
The freezing pint of benzene decreases by
0.45
o
C
when
0.2
g
of acetic acid is added to
20
g
of benzene. If acetic acid is associates to form a dimer in benzene, find the percentage association of acetic acid in benzene.
(
K
f
f
o
r
b
e
n
z
e
n
e
=
5.12
k
g
m
o
l
−
1
)
Q.
The freezing point of a solution containing
0.2
g
of acetic acid in
20
g
of benzene is lowered by
0.45
∘
C
.
. Calculate the degree of association
(
β
)
for acetic acid.
Given :
(
K
f
)
Benzene
=
5.12
K
k
g
m
o
l
−
1
Q.
The freezing point of benzene decreases by
0.45
∘
C
when 0.2g of acetic acid is added to 20g of benzene. If acetic acid associates to form a dimer in benzene, percentage association of acetic acid in benzene will be
(
K
f
for benzene = 5.12K kg
m
o
l
−
1
)
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