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Question

The freezing point of a solution containing 10 g of K3[Fe(CN)6] (mol wt. 329) in 200 gram of water (Kf=1.86 K Kg mol1) is:

A
2.57 C
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B
0.28 C
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C
5.7 C
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D
1.12 C
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Solution

The correct option is D 1.12 C
K3[Fe(CN)6]3K++[Fe(CN)6]3
i=1+(n1)α;α=100%
i = n = 4
ΔTf=i×Kf×m
m=molality=nsolutewsolvent(Kg)=103292001000
=10329×1000200=50329
=0.15=1.5×101
ΔTf=4×1.86×0.15=1.12
Tf=01.12=1.12 C

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