Question

The freezing point of a solution containing 28.335 $c{m}^3$ of ethylene glycol in 50 g water is found to be $–{34}^{\circ }$ C. Assuming ideal behaviour, calculate the density of ethylene glycol. $K_f$ for water 1.86 K kg $mo{l}^{-1}$.___

Answer 1

$W_{ethyleneglycol}=\frac{M_2\times \Delta T_f\times W_{water}}{1000\times k_f}$
$=\frac{62\times 34\times 50}{1000\times 1.86}=56.67g$
$d=\frac{W}{V}=\frac{56.67}{28.335}=2$