The frequency and work function of an incident photon are v and - 0- If v 0 is the threshold frequency- then necessary condition for the emission of photoelectron is

The correct option is C v≥ v _ 0 The photoelectric equation is given by 1 / 2 mV ^ 2 =hv h v _ 0 So, for maximum kinetic energy, frequency should be ...

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Standard XII

Physics

Saturation Current

The frequency...

Question

The frequency and work function of an incident photon are v and $ϕ_{0}$ . If $v_{0}$ is the threshold frequency, then necessary condition for the emission of photoelectron is

v < v_{0}

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v = \frac{v_{0}}{2}

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v \geq v_{0}

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None of these

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Solution

The correct option is C $v \geq v_{0}$
The photoelectric equation is given by
$\frac{1}{2} {m V}^{2} = h v - h v_{0}$
So, for maximum kinetic energy, frequency should be more than the cut-off frequency and wavelength should be less than the cut-off wavelength i.e. $v \geq v_{o}$

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The frequency and work function of an incident photon are v and ϕ0. If v0 is the threshold frequency, then necessary condition for the emission of photoelectron is

The correct option is C v≥v0The photoelectric equation is given by12mV2=hv−hv0So, for maximum kinetic energy, frequency should be more than the cut-off frequency and wavelength should be less than the cut-off wavelength i.e. v≥vo

The frequency and work function of an incident photon are v and $ϕ_{0}$ . If $v_{0}$ is the threshold frequency, then necessary condition for the emission of photoelectron is

The correct option is C $v \geq v_{0}$
The photoelectric equation is given by
$\frac{1}{2} {m V}^{2} = h v - h v_{0}$
So, for maximum kinetic energy, frequency should be more than the cut-off frequency and wavelength should be less than the cut-off wavelength i.e. $v \geq v_{o}$