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Question

The frequency distribution of marks obtained by students in a class test is given below. Draw frequency polygon and ogive.
Marks 0−10 10−20 20−30 30−40 40−50
Number of Students 5 10 14 10 3

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Solution

In order to construct a frequency polygon without a histogram, we first calculate the mid-points corresponding to the class intervals. The mid-points are then plotted against their respective frequencies. The curve obtained on joining the points is the frequency polygon.
Marks Mid Point Students
0 − 10 0+102=5 3
10 − 20 10+202=15 10
20 − 30 20+302=25 14
30 − 40 30+402=35 10
40 − 50 40+502=45 3


In order to construct the ogives, we first need to calculate the less than and the more than cumulative frequencies as follows.
Marks Cumulative Frequency
Less than 10
Less than 20
Less than 30
Less than 40
Less than 50
3
3 + 10 = 13
13 + 14 = 27
27 + 10 = 37
37 + 3 = 40
Marks Cumulative Frequency
More than 0
More than 10
More than 20
More than 30
More than 40
40
40 − 3 = 37
37 − 10 = 27
27 − 14 = 13
13 − 10 = 3


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