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Question

The frequency distribution table shows the number of mango trees in a grove and their yield of mangoes. Find the median of data.
No. of Mangoes 50 - 100 100 - 150 150 - 200 200 - 250 250 - 300
No. of trees 33 30 90 80 17

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Solution

Class
(Number of working hours)
Frequency
(Number of workers)
fi
Cumulaive frequency
less than the
upper limit
50 - 100 33 33
100 - 150 30 63
150 - 200
(Median Class)
90 153
200 - 250 80 233
250 - 300 17 250
N = 250

From the above table, we get
L (Lower class limit of the median class) = 150
N (Sum of frequencies) = 250
h (Class interval of the median class) = 50
f (Frequency of the median class) = 90
cf (Cumulative frequency of the class preceding the median class) = 63
Now, Median = L+N2-cff×h
=150+2502-6390×50
= 150 + 34.44
= 184.44 mangoes
= 184 mangoes
Hence, the median of data is 184 mangoes.

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