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Question

The frequency f of vibration of mass m suspended from a spring of spring contact k is given by f=c mx ky. Where c= dimensionless constant, then find the values of x and y.

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Solution

In this situation dimension of RHS=LHS
i.e, [f]=[cmxky]
[T1]=[Mx][MyT2y]=[Mx+yT2y], since [k]=[MT2]
comparing both sides we get,
x+y=0,and1=2yy=1/2
and x=y=1/2

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