The frequency of 3rd harmonic in an open organ pipe of length 33 cm. If the velocity of sound is 330 m/s, is
Given:
The length of the organ pipe l is, 33 cm
Velocity of sound v is, 330 m/s
To find:
The frequency of 3rd harmonic, n
where, p=3
Solution:
From the equation,
n=pv2l
n=3(330)2(33)(10−2)
n=1500Hz
so, the correct answer is option (c)