The frequency of a photon, having energy 100 eV is $(h = {6.610}^{- 34} J - s e c)$

$2.42 \times 10^{26} H z$

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$2.42 \times 10^{16} H z$

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$2.42 \times 10^{12} H z$

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$2.42 \times 10^{9} H z$

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Solution

The correct option is B
$2.42 \times 10^{16} H z$

$E = h v \Rightarrow 100 \times 1.6 \times 10^{- 19} = 6.6 \times 10^{- 34} \times V$
$\Rightarrow v = 2.42 \times 10^{16} H z$

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Similar questions

The frequency of a photon, having energy 100 eV is $(h = {6.610}^{- 34} J - s e c)$

100

h = 6.2 \times 10^{- 34} J s; 1 e V = 1.6 \times 10 - 19 J

= 6.625 \times 10^{- 34}

1.6 \times 10^{15} H z

(h = 6.6 \times 10^{- 34} J s)

8 e V

1.6 \times 10^{15} H z

h = 6 \times 10^{- 34} J s)

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