Question

The frequency of a tuning fork is $256$Hz and velocity of sound in air is $350$m/s. Find the distance covered by the wave when the fork completes $16$ vibrations.

Answer 1

$n=256Hz$,

$v=350\frac{m}{s}$

no. of vibrations $=16$

Distance covered by wave in one vibration is its wavelength $\left(\lambda \right)$

∴ Distance covered by wave in 16 Vibrations $=d=16\lambda$

$\lambda =\frac{v}{n}$

$d=16\lambda$

$=16\left(\frac{350}{256}\right)$

$= 21.875$

$d=21.875m$