The frequency of a wave is 6×1015 s−1. Its wave number will be:
A
105 cm−1
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B
2×107 m−1
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C
2×107 cm−1
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D
2×105 m−1
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Solution
The correct option is B2×107 m−1 We know that, c=λv where, c: speed of light; v: frequency; λ: wavelength Therefore, 1λ=vc Given, frequency (v)=6×1015 s−1 Hence, wavenumber −v=1λ=6×1015 s−13×108 m s −1=2×107 m−1