Question

The frequency of an alternating current is $50Hz$. The minimum time taken by it in reaching from zero to peak value is

• A. $5ms$
• B. $10ms$
• C. $20ms$
• D. $50ms$

Answer 1

The correct option is A $5ms$

$T=\frac{1}{f}=\frac{1}{50}s$
$t=\frac{T}{4}=\frac{1}{200}s$
$=5\times {10}^{-3}s$
$=5ms$