Question

The frequency of oscillation for a mass m will be proportional to :

Answer 1

when a opening of constant 'k' is extended by length x, the restoring

spring force is given by Hooke'n law.

F = kx

This restoring force provider necessary restoring force for oscillations.

$\Rightarrow F=m{w}^{2}x$ w : (Angular frequency of oscillation)

$\Rightarrow kx=m{w}^{2}x$

$\Rightarrow w=\sqrt{\frac{k}{m}}$

thus frequency;

$v=\frac{w}{2\pi }=\frac{1}{2\pi }\sqrt{\frac{k}{m}}$ (Ans)