The frequency of oscillation in an oscillation is

\frac{π}{ω}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 π}{ω}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{ω}{2 π}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{ω}{π}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{ω}{2 π}$
The relation between angular frequency $(ω)$ and time period (T) of a oscillation is given by, $ω = \frac{2 π}{T}$
The frequency of the oscillation , $f = \frac{1}{T} = \frac{ω}{2 π}$

Suggest Corrections

Similar questions

V = V_{0} s i n ω t f o r 0 \leq t \leq \frac{π}{ω}

V = - V_{0} s i n ω t f o r \frac{π}{ω} \leq t \leq \frac{2 π}{ω}

ω, ω^{2}

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} x + 1 & ω & ω^{2} ω & x + ω^{2} & 1 ω^{2} & 1 & x + ω \end{matrix} ∣ ∣ ∣ ∣ ∣

\int_{\frac{- π}{2}}^{\frac{π}{2}} f (x) d x

ω

y = {sin}^{2} ω t

x = A sin (ω t + ϕ)

x

Join BYJU'S Learning Program