The frequency of output and duty cycle of 555 timer, configured in astable mode (oscillator) is

7.69 k H z, 59.4 %

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5.65 k H z, 59.4 %

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7.69 k H z, 50 %

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5.65 k H z, 50 %

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Solution

The correct option is B $5.65 k H z, 59.4 %$
Given, $R_{L} = 2.2 k Ω, R_{2} = 4.7 k Ω, C = 0.022 μ F$
Output frequency, $f_{r} = \frac{1}{0.693 (R_{1} + 2 R_{2}) C}$
$= 5.65 k H z$
Duty cycle $= \frac{R_{1} R_{2}}{R_{1} + 2 R_{2}} \times 100 % = 59.4 %$

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A 555 t i m e r i s c o n f i g u r e d a s a n a s t a b l e m o d e w i t h R_{A} = 4 k Ω, R_{B} = 4 k Ω a n d C = 0.01 μ F . t h e n t h e d u l y c y c l e o f t h e o u t p u t w a v e w i l l b e . . . .

Ω

μ

R_{A} = 450 Ω; R_{B} = 0.5 k Ω; C = 1 μ F

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