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Question

The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be (Given : ionisation energy of H=2.18×1018Jatom1 and h=6.626×1034Js)

A
1.54×1015s1
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B
1.03×1015s1
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C
3.08×1015s1
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D
2×1015s1
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Solution

The correct option is C 3.08×1015s1
The frequency of radiation emitted when the electron falls from n=4 to n=1 in a hydrogen atom will be 3.08×1015s1
I.E=E1=2.18×1018J/atom
E1=I.E=2.18×1018J/atom
En=E1n2
E4=E142
E4=2.18×1018J/atom42
E4=1.36×1019J/atom
ΔE=E1E4
ΔE=2.18×1018J/atom(1.36×1019J/atom)
ΔE=2.04×1018J/atom
The frequency ν=ΔEh
ν=2.04×1018J/atom6.626×1034Js
ν=3.08×1015s1

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