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Question

The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be

(Given ionization energy of H = 2.18 × 1018 J atom1 and h = 6.625 × 1034 Js)


A

3.08 × 1015 s1

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B

2.00 × 1015 s1

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C

1.54 × 1015 s1

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D

1.03 × 1015 s1

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Solution

The correct option is A

3.08 × 1015 s1


From Bohr's postulates, we know

[Frequency of radiation] ν = 3.289 × 1015 × Z2 [1n21 1n22] Hz

Now, ν = 3.289 × 1015 × (1)2 [112 142]

ν = 3.289 × 1015 × [1 116]

ν = 3.289 × 1015 × 1516

ν = 3.0834 × 1015 Hz


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