The frequency of radiations emitted when electron falls from n = 4, to n = 1, in H-atom would be:
(Given E₁ for H=2.18×10^-18J atom ^-1 and h=6.625 ×10^-34 Js.)

1.54×10¹⁵ s^-1

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1.03×10¹⁵ s^-1

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3.08×10¹⁵ s^-1

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2.0×10¹⁵ s^-1

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Solution

The correct option is C
3.08×10¹⁵ s^-1

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Similar questions

n = 4

n = 1

H = 2.18 \times 10^{- 18} J a t o m^{- 1}

h = 6.625 10^{- 34} J s

n = 4

n = 1

h = 6.625 \times 10^{- 34}

The frequency of radiations emitted when electron falls from n = 4, to n = 1, in H-atom would be:

(Given E₁ for H=2.18×10^-18J atom ^-1 and h=6.625 ×10^-34 Js.)

The frequency of radiation emitted when the electron falls from n = 4 to n = 1 in a hydrogen atom will be

(Given ionization energy of $H = 2.18 \times 10^{- 18} J a t o m^{- 1}$ and $h = 6.625 \times 10^{- 34} J s$ )

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