wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The frequency of revolution of an electron in nth orbit is fn. If the electron makes a transition from the nth orbit to (n−1)th orbit, then the relation between the frequency (v) of emitted photon and fn will be :

A
v=f2n
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
v=fn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
v=1fn
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
v=fn
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B v=fn

f= mZ2e4/4n3h3ϵ02

f(n-1)=fn.(n/n-1)^3


and

E=-mZ2e4/8ε02h2n2


so, E=-fhn/2


now for transition within n to (n-1)

hv=f(n).h.n/2-f(n-1).h.n/2

v=f(n)/2{[n^4-(n-1)^4]/n^3}

so v=Kf(n)

v proportional to f(n) but some of its multiple



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy Levels
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon