The frequency of the first overtone produced in an air column enclosed in an open pipe is $250 h z$ If the velocity of sound in air is $340 m s^{- 1}$ , then calculate the length of the pipe.

106 m

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116 m

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126 cm

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136 cm

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Solution

The correct option is D
136 cm

Correct option is D: 136 cm
Step 1: Given:
Frequency $(f) = 250 h z$
Velocity of sound $(v) =$ $340 m s^{- 1}$
Find: The length of the pipe
Step 2: Finding length of the pipe
The frequency of the first overtone produced in an air column enclosed in an open pipe can be calculated as,
$f_{2} = \frac{2 v}{2 l} l = \frac{v}{f} l = \frac{340 m s^{- 1}}{250 h z} l = 1.36 m l = 136 c m$
Hence, length of the organ pipe will be 136 cm

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The frequency of the first overtone produced in an air column enclosed in an open pipe is 250hz If the velocity of sound in air is 340ms-1, then calculate the length of the pipe.

The frequency of the first overtone produced in an air column enclosed in an open pipe is $250 h z$ If the velocity of sound in air is $340 m s^{- 1}$ , then calculate the length of the pipe.