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Question

The frequency of vibration f of a mass m suspended from a spring of spring constant K is given by a relation of this type f =CmxKy; where C is a dimensionless quantity. The value of x and y are

A
x = 12, y = 12
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B
x = -12, y = - 12
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C
x = 12, y = - 12
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D
x = - 12, y = 12
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Solution

The correct option is D x = - 12, y = 12

By putting the dimensions of each quantity both sides we get [T1]=[M]x[MT2]y
Now comparing the dimenstions of quantities in both sides we get x+y =0 and 2y =1
x = - 12, y = 12


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