The frequency polygon of a frequency distribution is shown below.
Answer the following about the distribution from the histogram.
(i) What is the frequency of the class interval whose class mark is 15?
(ii) What is the class interval whose class mark is 45?
(iii) Construct a frequency table for the distribution.
(i) 18
(ii) 40 – 50
(iii) As the class marks of consecutive overlapping class intervals are 5, 15, 25, 35, 45, 55 we find the class intervals are 0
– 10, 10 – 20, 20 – 30, 30 – 40, 40 – 50, 50 – 60.
Therefore, the frequency table is constructed as below.
Class IntervalFrequency0−101010−201820−301430−402640−50850−6018