The frequency table is shown. Find the median for the following data:
Number of hours
$2$
$4$
$6$
$8$
Frequency
$13$
$15$
$24$
$11$

2

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4

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6

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8

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Solution

The correct option is C $6$

Number of hours

Frequency

C.f

$2$

$13$

$13$

$4$

$15$

$28$

$6$

$24$

$52$

$8$

$11$

$63$

Sum of frequency $= 63 (o d d n u m b e r)$
Median is $(\frac{n + 1}{2}) p o s i t i o n$
Median is at $= (\frac{63 + 1}{2}) = \frac{64}{2} = 32$
$32$ is greater than $28$ but less than $52$
Median is $6 A n s$

Suggest Corrections

Similar questions

Class	$0 - 5$	$6 - 11$	$12 - 17$	$18 - 23$	$24 - 29$
Frequency	$13$	$10$	$15$	$8$	$11$

Class-intervals	$0 - 4$	$4 - 8$	$8 - 12$	$12 - 16$	$16 - 20$	$20 - 24$
Frequency	$4$	$7$	$10$	$15$	$11$	$6$

5

12, 12, 11, 12, 2, 3, 3, 3, 4, 4, 2, 2, 5, 6, 7, 4, 7, 8, 15, 15, 20, 20

Calculate the mean deviation about the median of the following frequency distribution :

$\begin{matrix} x_{i} & 5 & 7 & 9 & 11 & 13 & 15 & 17 f_{i} & 2 & 4 & 6 & 8 & 10 & 12 & 8 \end{matrix}$

$x$	$2 - 4$	$4 - 6$	$6 - 8$	$8 - 10$	$10 - 12$
frequency	$1$	$3$	$2$	$4$	$10$

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