The frequency table shows the number of chocolates that were distributed among the students of different grades. Find the median number of grade students.
Grade
$6$
$7$
$8$
Number of chocolates distributed
$10$
$24$
$11$

6

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Solution

The correct option is B $7$

Grade

Number of chocolates

Position

$6$

$10$

$10$

$7$

$24$

$34$

$8$

$11$

$45$

Sum of number of chocolates $= 10 + 21 + 11 = 45 (o d d n u m b e r)$
Median at $(\frac{n + 1}{2}) p o s i t i o n = (\frac{45 + 1}{2}) = 23$
$23$ rd position comes after $10$ th but before $34$ th position
So, $M e d i a n = 7$

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Grade	Number of chocolates	Position
$6$	$10$	$10$
$7$	$24$	$34$
$8$	$11$	$45$

The frequency table shows the number of chocolates that were distributed among the students of different grades. Find the median number of grade students.Grade678Number of chocolates distributed102411

The correct option is B 7 Grade Number of chocolates Position 6 10 10 7 24 34 8 11 45 Sum of number of chocolates =10+21+11=45(oddnumber)Median at (n+12)position=(45+12)=2323rd position comes after 10th but before 34th positionSo, Median=7

The frequency table shows the number of chocolates that were distributed among the students of different grades. Find the median number of grade students.
Grade
$6$
$7$
$8$
Number of chocolates distributed
$10$
$24$
$11$