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Question

The friction coefficient between the two blocks shown in figure is μ but the floor is smooth. Assume the entire system is kept inside an elevator coming down with an acceleration a < g.


A

2m(g-a),

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B

2m(g-a),

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C

2,

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D

None of these

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Solution

The correct option is A

2m(g-a),


As it is at rest with respect to the elevator

Fx=0 Block M,MN=T

Fy=0 T=μm(ga) .........(2)

N+ ma = Mg

N=m(g-a) .........(1)

F=T+μN
=T+ μm(g-a) ..........(3)

From (2) and (3)

F= 2μm (g - a)

Case(B)

When F=4μm(g-a) For block M
For block m, Fx=Ma1
Fx=ma1

The magnitude of acceleration will be the same as they are constrained by the string.

FTμM(ga)=Ma1 (For block m)

T - μm(ga)=Ma1 (For block M)

=F - 2μm(ga)=(M+m)a1

4μm(ga)2μm(ga)=(M+m)a1a1=2μm(ga)M+m


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