The friction of the air causes vertical retardation equal to one-tenth of the acceleration due to gravity (take $g = 10 m s^{- 2}$ ). Find the decrease in the time of flight.(in percent)

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Solution

The correct option is A 9
$T = \frac{2 u sin θ}{g} ∴ \frac{T_{1}}{T_{2}} = \frac{g_{2}}{g_{1}} = \frac{g + \frac{g}{10}}{g} = \frac{11}{10}$
Fractional decrease in time of flight = $\frac{T_{1} - T_{2}}{T_{1}} = \frac{1}{11}$
Percentage decrease = $9 %$

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The friction of the air causes vertical retardation equal to one-tenth of the acceleration due to gravity (take g=10ms−2). Find the decrease in the time of flight.(in percent)

The correct option is A 9T=2usinθg∴T1T2=g2g1=g+g10g=1110Fractional decrease in time of flight =T1−T2T1=111Percentage decrease = 9%

The friction of the air causes vertical retardation equal to one-tenth of the acceleration due to gravity (take $g = 10 m s^{- 2}$ ). Find the decrease in the time of flight.(in percent)

The correct option is A 9
$T = \frac{2 u sin θ}{g} ∴ \frac{T_{1}}{T_{2}} = \frac{g_{2}}{g_{1}} = \frac{g + \frac{g}{10}}{g} = \frac{11}{10}$
Fractional decrease in time of flight = $\frac{T_{1} - T_{2}}{T_{1}} = \frac{1}{11}$
Percentage decrease = $9 %$