The Friedel-Crafts reaction of benzene with propene proceeds through the formation of -

{C H}_{3} {C H}_{2} + C H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{3} + C {H C H}_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{C H}_{3} {C H}_{2} {C H}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{C H}_{3} {C H C H}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B ${C H}_{3} + C {H C H}_{3}$
In Friedel Craft's reaction the reaction proceed with formation of secondary carbocation because it is more stable than primary carbocation.

Suggest Corrections

Similar questions

H O C l (C l_{2} + H_{2} O)

Write the IUPAC name of $C H_{3} - C H_{2} - C H (C H_{3}) - C H_{2} - C H_{2} - C H_{2} - C H_{3}$ .

C H_{3} - C H_{2} - C H_{2} - C H (C H_{3}) - C H_{3}

C H_{3} - C H (C H_{2} - C H_{3}) - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H (C H_{3}) - C H (C H_{3}) - C H_{2} - C H_{3}

C H_{3} - C H_{2} - C H (C H_{3}) - C (C_{4} H_{9}) (C H_{3}) - C H_{3}

Join BYJU'S Learning Program