Question

The frustum cone curved surface area is 230 $\pi c{m}^2$. The upper and lower circle area of a cone is 12.5 and 16.5 cm. Find the total surface area. (Use $\pi$ = 3.14).

• A. 711.2 $c{m}^3$
• B. 721.2 $c{m}^3$
• C. 751.2 $c{m}^3$
• D. 731.2 $c{m}^3$

Answer 1

The correct option is C 751.2 $c{m}^3$

Total surface area = $\pi (R+r)s+A_1+A_2$

Curved surface area = $\pi (R+r)s\Rightarrow 230\pi m^2$

$A_1=12.5cm,A_2=16.5cm$

Therefore, Total surface area =$230\times 3.14+12.5+16.5$

TSA = 751.2 $c{m}^3$