Question

The frustum cone curved surface area is 360 $m^2$. The upper and lower circle area of a cone is 12 and 16 m. Find the total surface area.

• A. 378 $m^3$
• B. 388 $m^3$
• C. 398 $m^3$
• D. 408 $m^3$

Answer 1

Answer: (B)

388 $m^3$

Total surface area = $\pi (R+r)s+A_1+A_2$

Curved surface area = $\pi (R+r)s\Rightarrow 360m^2$

$A_1=16m,A_2=12m$

Therefore, Total surface area = 360 + 16 +12

TSA = 388 $m^3$