The frustum cone curved surface area is 389.13 $c m^{3}$ . The upper and lower circle area of a cone is 2.5 and 6.5 cm. Find the total surface area.

368.18

c m^{3}

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378.18

c m^{3}

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388.18

c m^{3}

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398.18

c m^{3}

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Solution

The correct option is D 398.18 $c m^{3}$
Total surface area = $π (R + r) s + A_{1} + A_{2}$
Curved surface area = $π (R + r) s \Rightarrow 389.13 c m^{2}$
$A_{1} = 2.5 c m, A_{2} = 6.5 c m$
Therefore, Total surface area $= 389.13 + 2.5 + 6.5$
TSA = 398.18 $c m^{3}$

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The frustum cone curved surface area is 389.13 cm3. The upper and lower circle area of a cone is 2.5 and 6.5 cm. Find the total surface area.

The correct option is D 398.18 cm3Total surface area = π(R+r)s+A1+A2Curved surface area = π(R+r)s⇒389.13cm2A1=2.5cm,A2=6.5cmTherefore, Total surface area=389.13+2.5+6.5TSA = 398.18 cm3

The frustum cone curved surface area is 389.13 $c m^{3}$ . The upper and lower circle area of a cone is 2.5 and 6.5 cm. Find the total surface area.

The correct option is D 398.18 $c m^{3}$
Total surface area = $π (R + r) s + A_{1} + A_{2}$
Curved surface area = $π (R + r) s \Rightarrow 389.13 c m^{2}$
$A_{1} = 2.5 c m, A_{2} = 6.5 c m$
Therefore, Total surface area $= 389.13 + 2.5 + 6.5$
TSA = 398.18 $c m^{3}$