The frustum cone curved surface area is 230 $π c m^{2}$ . The upper and lower circle area of a cone is 12.5 and 16.5 cm. Find the total surface area. (Use $π$ = 3.14).

Q. A sphere of radius 100 mm shrinks to radius 98 mm, then the approximate decrease in its volume is
(a) 12000 π mm³
(b) 800 π mm³
(c) 80000 π mm³
(d) 120 π mm³

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The frustum cone curved surface area is 600 mm3. The upper and lower circle area of a cone is 25 and 35 mm. Find the total surface area.

The correct option is A 660 mm3Total surface area = π(R+r)s+A1+A2Curved surface area = π(R+r)s⇒600mm2A1=25mm,A2=35mmTherefore, Total surface area = 600 + 25 + 35TSA = 660 mm3

The frustum cone curved surface area is 600 $m m^{3}$ . The upper and lower circle area of a cone is 25 and 35 mm. Find the total surface area.

The correct option is A 660 $m m^{3}$
Total surface area = $π (R + r) s + A_{1} + A_{2}$
Curved surface area = $π (R + r) s \Rightarrow 600 m m^{2}$
$A_{1} = 25 m m, A_{2} = 35 m m$
Therefore, Total surface area = 600 + 25 + 35
TSA = 660 $m m^{3}$