The function 12 x 5-45 x 4-40 x 3-6 has a minimum atA- x -0B- x-1C- x -2D- x-1

The correct option is C x=2 f^1(2) = 0,f^11(2) gt; 0 ⇒ f(x) has minimum at x = 2 ...

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Question

The function $12 x^{5} - 45 x^{4} + 40 x^{3} + 6$ has a minimum at

x=0

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x=1

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x=2

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x=-1

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