Question

The function at $y=\sqrt{\left(\frac{1}{2}\right)-{\cos }^{2}x}$

then the value of x when y = 0

• A. $x=\frac{\pi }{4}$
• B. $x=\frac{3\pi }{4}$
• C. $x=\frac{5\pi }{4}$
• D. $x=\frac{7\pi }{4}$

Answer 1

Answer: (A), (B), (C), (D)

The correct options are
A $x=\frac{\pi }{4}$
B $x=\frac{3\pi }{4}$
C $x=\frac{5\pi }{4}$
D $x=\frac{7\pi }{4}$

For $y=0$

${\cos }^{2}x=\frac{1}{2}$

$\cos x=\pm \frac{1}{\sqrt{2}}$

The above is true for all given values of x.