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Question

The function f(x)=min{sin[m]x,cos[m]x} has π as fundamental period then range of m is given by

A
[1,2)
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B
[3,4]
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C
[4,5)
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D
{4}
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Solution

The correct option is C [4,5)
Given f(x)=min{sin[m]x,cos[m]x}
f(x)=sin[m]x

Period of sin[m]x is 2π[m]

But given period of f(x) is π

2π[m]=π

[m]=2

[m]=4

Hence, 4m<5

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