The function f(x)=x3−x2−x−114 is graphed in the xy plane above. If k is a constant such that the equation f(x)=k has three real solutions, which of the following could be the value of k?
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Solution
f(x)=x3−x2−x−114
From graph, there is one local maxima and one local minima
f(x)=3x2−2x−1
will have two real solutions
We have to chose k such that f(x)=k have three real solutions
f(x)=x3−x2−x−2.75=kFor f(x) to have 3 solutions, the last co efficient −2.75 needs to be positive and for that k must be equal to −3