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Question

The function y=4cosθsinθ+2 θ[0,π2] is

A
always increasing
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B
always decreasing
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C
increasing in [0,π4]
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D
decreasing in [0,π4]
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Solution

The correct option is B always decreasing
y=4cosθsinθ+2y=4sinθ(sinθ+2)4cosθ(cosθ)(sinθ+2)2y=48sinθ(sinθ+2)2

For θ[0,π2]; sinθ0
So y<0 θ[0,π2]
Therefore the function is always decreasing.

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