Question

The function $f:(-\infty ,-1)\to (0,e^5)$ defined by $f\left(x\right)=e^{x^3-3x+2}$ is

• A. one-one and into
• B. one-one and onto
• C. many-one and into
• D. many-one and onto

Answer 1

The correct option is B one-one and onto

From the graph we can say that for $f:(-\infty ,-1)\to (0,e^5)$ i.e for a domain of $(-\infty ,-1)$ $f\left(x\right)$ is a one one and onto function.
However for $R\to R$ it is not one-one.