The function f is defined by f x - left begin matrix 1- x - 8 x 0endmatrix right Draw the graph of f x -

Here, f(x)=1 x for x lt;0. So, f( 4)=1 ( 4)=5 f( 3)=1 ( 3) = 4 f( 2) = 1 ( 2)=3 f( 1)=1 ( 1)=2 etc Also, f(x) = x + 1, for x gt; 0 and f(1) = 2, f(2) ...

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Byju's Answer

Standard XII

Mathematics

Using Graph to Find Range of a Function

The function ...

Question

The function f is defined by
$f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} 1 - x, & x < 0 1, & x = 0 x + 1, & x > 0 \end{matrix}$ Draw the graph of f(x).

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Solution

Here,
$f (x) = 1 - x$ for $x < 0$ . So,
$f (- 4) = 1 - (- 4) = 5 f (- 3) = 1 - (- 3) = 4 f (- 2) = 1 - (- 2) = 3 f (- 1) = 1 - (- 1) = 2 e t c$
Also, f(x) = x + 1, for x > 0
and f(1) = 2, f(2) = 3, f(3) = 4, f(4) = 5 and so on.
Thus, the graph of f is as shown below:

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The function f is defined by f(x)=⎧⎪⎨⎪⎩1−x,x<01,x=0x+1,x>0 Draw the graph of f(x).

Here, f(x)=1−x for x<0. So, f(−4)=1−(−4)=5f(−3)=1−(−3)=4f(−2)=1−(−2)=3f(−1)=1−(−1)=2 etc Also, f(x) = x + 1, for x > 0 and f(1) = 2, f(2) = 3, f(3) = 4, f(4) = 5 and so on. Thus, the graph of f is as shown below:

The function f is defined by
$f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} 1 - x, & x < 0 1, & x = 0 x + 1, & x > 0 \end{matrix}$ Draw the graph of f(x).

Here,
$f (x) = 1 - x$ for $x < 0$ . So,
$f (- 4) = 1 - (- 4) = 5 f (- 3) = 1 - (- 3) = 4 f (- 2) = 1 - (- 2) = 3 f (- 1) = 1 - (- 1) = 2 e t c$
Also, f(x) = x + 1, for x > 0
and f(1) = 2, f(2) = 3, f(3) = 4, f(4) = 5 and so on.
Thus, the graph of f is as shown below: